mysql中sql實現查詢當天、昨天、本月、季度的語句

本文章收藏了關於mysql中sql實現查詢當天、昨天、本月、季度的語句，有需要學習的朋友可參考一下。  代碼如下 復制代碼

查詢

今天
select * from 表名 where to_days(時間字段名) = to_days(now()); 
昨天
 

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 時間字段名) <= 1 
7天
 

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(時間字段名) 
近30天
 

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(時間字段名) 

本月
 

SELECT * FROM 表名 WHERE DATE_FORMAT( 時間字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ ) 
上一月
 

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 時間字段名, ‘%Y%m’ ) ) =1 
同時，再附上 一個 mysql官方的相關document

#查詢本季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查詢上季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查詢本年數據
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查詢上年數據
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

 

查詢當前這周的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查詢上周的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查詢當前月份的數據
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

查詢距離當前現在6個月的數據
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查詢上個月的數據
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select *
from user
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select *
from [ user ]
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select *
from [ user ]
where pudate between 上月最後一天
and 下月第一天

where   date(regdate)   =   curdate();

select   *   from   test   where   year(regdate)=year(now())   and   month(regdate)=month(now())   and   day(regdate)=day(now())

SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30

http://dev.mysql.com/doc/refman/5.1/zh/tutorial.html