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mysql“ Every derived table must have its own alias”問題

在mysql中查詢時發現mysql提示Every derived table must have its own alias錯誤了,意思就是要有一個別名了,這個問題就這麼解決了。


我的查詢語句

select count(*) from (select * from ……)  total;

錯誤提示

Every derived table must have its own alias

這句話的意思是說每個派生出來的表都必須有一個自己的別名

一般在多表查詢時,會出現此錯誤。

因為,進行嵌套查詢的時候子查詢出來的的結果是作為一個派生表來進行上一級的查詢的,所以子查詢的結果必須要有一個別名

把MySQL語句改成:select count(*) from (select * from ……) as total;

問題就解決了,雖然只加了一個沒有任何作用的別名total,但這個別名是必須的

 代碼如下 復制代碼


select name1 name, java, jdbc, hibernate,total
from (select sc1.name name1, sc1.mark java
 from student_course2 sc1
 where sc1.course='java') as a,
 (select sc2.name name2, sc2.mark jdbc
 from student_course2 sc2
 where sc2.course='jdbc') as b,
 (select sc3.name name3, sc3.mark hibernate
 from student_course2 sc3
 where sc3.course='hibernate') as c,
(select sc4.name name4,sum(sc4.mark) total
from student_course2 sc4 group by sc4.name) as d
  where name1=name2 and name2=name3 and name3=name4 order by total ASC;

結果正確:

+----------+------+------+-----------+-------+
| name     | java | jdbc | hibernate | total |
+----------+------+------+-----------+-------+
| wangwu   |   40 |   30 |        20 |    90 |
| lisi     |   70 |   60 |        50 |   180 |
| zhangsan |  100 |   90 |        80 |   270 |
+----------+------+------+-----------+-------+
3 rows in set (0.02 sec)

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