萬盛學電腦網 >> 腳本專題 >> javascript >> JQuery實現帶排序功能的權限選擇實例
JQuery實現帶排序功能的權限選擇實例
本文實例講述了JQuery實現帶排序功能的權限選擇。分享給大家供大家參考。具體實現方法如下：
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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> <script src="jquery-1.6.2.min.js" type="text/javascript"></script> <style type="text/css"> select{width:100px;height:100px;float:left;margin:10px;} #main{float:left;width:100px;text-align:center;margin:10px;} #main input{width:100px;} </style> <script type="text/javascript"> var myJson = [{ "id": "1", "Name": "劉德華", "Age": "52" }, { "id": "2", "Name": "文章", "Age": "26" }, {"id":"3","Name":"孫紅雷","Age":"40"}, { "id": "4", "Name": "葛優", "Age": "58"}]; $(function () { var $leftSel = $("#leftSel"); for (var i = 0; i < myJson.length; i++) { var $option = $("<option sortID='" + myJson[i].id + "' value='" + myJson[i].Name + "'>" + myJson[i].id + "," + myJson[i].Name + "</option>"); $option.appendTo($leftSel); } $("#btnMoveLeft").click(function () { var $selOptions = $("#leftSel option:selected"); $selOptions.appendTo($("#rightSel")).attr("selected", false); }); $("#btnMoveLeftAll").click(function () { var $allLeftOptions = $("#leftSel option"); $allLeftOptions.appendTo($("#rightSel")).attr("selected", false); }); $("#btnMoveRight").click(function () { var $selOptions = $("#rightSel option:selected"); $selOptions.appendTo($leftSel).attr("selected", false); }); $("#btnMoveRightAll").click(function () { var $allRightOptions = $("#rightSel option"); $allRightOptions.appendTo($leftSel).attr("selected", false); }); $("#btnMoveLeftSort").click(function () { //把右邊列表的內容添加到左邊，並按sortID屬性進行排序 $("#rightSel option").appendTo($("#leftSel")); var $sortArray = $("#leftSel option").sort(function (prev, next) { var prevSortID = parseInt(prev.sortID); var nextSortID = parseInt(next.sortID); if (prevSortID > nextSortID) { return 1; //交換位置 } else { return -1; } }); $("#leftSel").empty().append($sortArray); }); }); </script> </head> <body> <select id="leftSel" multiple="multiple"> </select> <div id="main"> <input id="btnMoveLeft" type="button" value="-->" /> <input id="btnMoveLeftAll" type="button" value="==>" /> <input id="btnMoveRight" type="button" value="<--" /> <input id="btnMoveRightAll" type="button" value="<==" /> <input id="btnMoveLeftSort" type="button" value="<--Sort" /> </div> <select id="rightSel" multiple="multiple"> </select> </body> </html>希望本文所述對大家的jQuery程序設計有所幫助。
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