PHP日期函數date格式化UNIX時間的方法

 這篇文章主要介紹了PHP日期函數date格式化UNIX時間的方法,實例分析了php中date函數的使用技巧,需要的朋友可以參考下

   

本文實例講述了PHP日期函數date格式化UNIX時間的方法。分享給大家供大家參考。具體分析如下：

日期函數可以根據指定的格式將一個unix時間格式化成想要的文本輸出

使用到函數語法如下

? 1 2 string date (string $Format); string date (string $Format, int $Time);

下面是演示代碼

? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 <?php echo "When this page was loaded,n"; echo 'It was then ', date ('r'), "n"; echo 'The currend date was ', date ('F j, Y'), "n"; echo 'The currend date was ', date ('M j, Y'), "n"; echo 'The currend date was ', date ('m/d/y'), "n"; echo 'The currend date was the ', date ('jS of M, Y'), "n"; echo 'The currend time was ', date ('g:i:s A T'), "n"; echo 'The currend time was ', date ('H:i:s O'), "n"; echo date ('Y'); date ('L')?(print ' is'):(print ' is not'); echo " a leap yearn"; echo time ('U'), " seconds had elapsed since January 1, 1970.n"; ?>

輸出結果如下

? 1 2 3 4 5 6 7 8 9 It was then Sat, 26 Dec 2009 07:09:51 +0000 The currend date was December 26, 2009 The currend date was Dec 26, 2009 The currend date was 12/26/09 The currend date was the 26th of Dec, 2009 The currend time was 7:09:51 AM GMT The currend time was 07:09:51 +0000 2009 is not a leap year 1261811391 seconds had elapsed since January 1, 1970.

希望本文所述對大家的php程序設計有所幫助。