從 MSSQL 中導出一個文章表,需要插入到 PHPCMS 中的內容表 phpcms_content 去,需要做到文章可以發布到不同的欄目中去。也就是說,需要復制一條記錄,並修改其 catid,再插入到表尾的位置上
代碼如下 復制代碼INSERT INTO phpcms_content (SELECT ".$r[$i]['aid']." + 520, ".$r[$i]['cateid'].", news_catid, catid, typeid, areaid, title, style, thumb, keywords, keywords, posids, url, listorder, status, userid, username, inputtime, updatetime, searchid, islink, prefix FROM phpcms_content WHERE contentid = '".$r[$i-1]['aid']."')
大致為:insert into a SELECT id+1, ...(其它字段) FROM a ;
下面PHP具體程序:
代碼如下 復制代碼$query = "SELECT * FROM articleincategory ORDER BY ArticleID ";
$result = $connector -> query($query);
$i = 0;
while($myrow = $connector -> fetch_array($result))
{
$r[$i]['aid'] = $myrow["ArticleID"];
$r[$i]['cateid'] = $myrow["CategoryID"];
$i++;
}
for($i = 0; $i < count($r); $i++)
{
if($i > 0)
{
if( $r[$i]['aid'] == $r[$i-1]['aid'] )
{
echo '第 '. $i. ' 條數據 '. $r[$i]['aid'] .' 與前一條數據 '. $r[$i-1]['aid'] .' 重復'.'<br/>';
$sql = " INSERT INTO phpcms_content (SELECT ".$r[$i]['aid']." + 520, ".$r[$i]['cateid'].", news_catid, catid, typeid, areaid, title, style, thumb, keywords, keywords, posids, url, listorder, status, userid, username, inputtime, updatetime, searchid, islink, prefix FROM phpcms_content WHERE contentid = '".$r[$i-1]['aid']."') ";
//$sql = " INSERT INTO phpcms_c_news (SELECT ".$r[$i]['aid']." + 520, template, titleintact, content, groupids_view, readpoint, author, copyfrom, paginationtype, maxcharperpage, sub_title FROM phpcms_c_news WHERE contentid = '".$r[$i-1]['aid']."') ";
echo $sql.'<br />';
//$result = $connector -> query($sql);
//INSERT INTO test (SELECT id + 10, name, class, score FROM test WHERE id = '1');
}
else if( $r[$i]['aid'] != $r[$i-1]['aid'] )
{
$sql = " UPDATE phpcms_content SET origin_cateid = '".$r[$i]['cateid']."' WHERE contentid = '".$r[$i]['aid']."' ";
echo $sql.'<br />';
//$result = $connector -> query($sql);
}
}
}
如果不需要插入,則更簡單:insert into mytable (select * from mytable where id=1) ON DUPLICATE KEY UPDATE id=2;